POMÓŻCIE

^ - do potęgi / - liczba w ułamku * - mnożenie [] - drugi nawias a) (3^-2)^2 = 3^-4 = (1/3)^4 = 1/81 b) (1/2)^-4 = 2^4 = 16 c) (2^-3)*[(1/2)^-3] = [(1/2)^3]*(2^3) = 1^3 = 1 d) (9^3)*(3^-5) = 729*[(1/3)^5] = 729*(1/243) = 729/243 = 3 e) [(2^-3)*(4^-2)]/(2^-6) = [(1/2)^3*(1/4)^2]/[(1/2)^6] = = [(1/8)*(1/16)]/(1/64) = (1/128)/(1/64) = (1/128)*(64/1) = 64/128 = 1/2 f) (10^-2)/[(5^-6)*(25^2)] = [(1/10)^2]/[(1/5)^6*625] = (1/100)/[(1/25)*1] = = (1/100)*(25/1) = 25/100 = 1/4 g)[(6^4)*(9^-4)]/[(4^2)*(12^-1)] = [1296*(1/9)^4]/[8*(1/12)^1 = =[1296*(1/729)]/(8/12) = (1296/729)*(12/8) = 1944/729 = 2(487/729)